Merge Sort ( C & Python 3 )

Merge Sort 

Merge sort is one of the most efficient sorting algorithms. It works on the principle of Divide and Conquer. Merge sort repeatedly breaks down a list into several sublists until each sublist consists of a single element and merging those sublists in a manner that results into a sorted list.

Algorithm:-

Conceptually, a merge sort works as follows :
  • Divide the unsorted list into n sublists, each containing 1 element (a list of 1 element is considered sorted).
  • Repeatedly merge sublists to produce new sorted sublists until there is only 1 sublist remaining. This will be the sorted list.
A pictorial representation of Merge Sort :-

Pictorial Presentation: Merge sort

Speed of Merge Sort : - 

Best case Scenario   : - θ( n log n )
Worst Case Scenario : - θ( n log n )

So, merge sort is one of the most efficient ways of sorting. 

The main algorithm of Merging explained with the help of a program in Python 3. ( Not the complete program )
"""
The programming is about taking two sorted list and merging it 
into a bigger sorted list. 

The backbone of sorting or how merge sort works.

@author: Abhishek

"""
def merging(a,b,m,n):
    print("The first sorted list is ",a,m,"\n The second sorted list is ",b,n)
    i=j=k=0
    c=[]
    while(i<m and j<n):
        if(a[i]>b[j]):
            c.append(b[j])
            j=j+1
            k=k+1
        else:
            c.append(a[i])
            i=i+1
            k=k+1
    while(i<m):
        c.append(a[i])
        i=i+1
    while(j<n):
        c.append(b[j])
        j=j+1
    print(c)
    
a=list(int(x) for x in input("Enter the first list : ").rstrip().split())
b=list(int(x) for x in input("Enter the second list : ").rstrip().split())
a.sort()
b.sort()
merging(a,b,len(a),len(b))
Merge Sort complete program in Python 3
"""
Merge Sort Algorithm in Python 3
@author: Abhishek

"""

def merge(array,start,middle,end):
    
    n1=middle-start+1
    n2=end-middle
    
    left=[0]*n1
    right=[0]*n2
    
    for i in range(0,n1):
        left[i]=array[start+i]
    for i in range(0,n2):
        right[i]=array[middle+1+i]
    
    i=0
    j=0
    k=start
    
    while(i<n1 and j<n2):
        if(left[i]<right[j]):
            array[k]=left[i]
            i+=1
        else:
            array[k]=right[j]
            j+=1
        k+=1
    
    while(j<n2):
        array[k]=right[j]
        j+=1
        k+=1
    while(i<n1):
        array[k]=left[i]
        i+=1
        k+=1
                               
    
    
def merge_sort(array,start,end):
    if(end>start):
        middle=(end+start)//2
        merge_sort(array,start,middle)
        merge_sort(array,middle+1,end)
        merge(array,start,middle,end)
        

array=list(map(int,input("Enter an array : ").split()))
sorted_array=merge_sort(array,0,len(array)-1)
print("The sorted array is ",array)

Output of the Python 3 program 
Enter an array : 3 1 4 1 5 9 2 6 5 4
The sorted array is  [1, 1, 2, 3, 4, 4, 5, 5, 6, 9]

Merge Sort complete program in C
/*

@uther - Abhishek
Merge Sort in C

*/

#include <stdio.h>
#include <stdlib.h>

void merge(int* ,int , int ,int );
void merge_sort(int* , int ,int );
int main()
{
    int n,i;
    printf("\nEnter the number of items to be sorted : ");
    scanf("%d",&n);

    int array[n];

    for(i=0;i<n;i++)
    {
        printf("\nEnter the item no %d : ",i+1);
        scanf("%d",&array[i]);
    }

    merge_sort(array,0,n-1);

    printf("\nThe Sorted list is as follows :- ");
    for(i=0;i<n;i++)
    {
        printf("\n\nThe item no %d of the sorted list is : %d",i+1,array[i]);
    }

}


void merge_sort(int *array, int start, int end)
{
    int middle;
    if(start<end)
    {
        middle=(start+end)/2;
        merge_sort(array,start,middle);
        merge_sort(array,middle+1,end);
        merge(array,start,middle,end);
    }
}

void merge(int *array, int start, int middle, int end)
{
    int n1,n2;
    int i,j,k;


    n1=middle-start+1;
    n2=end-middle;

    int left[n1],right[n2];

    for(i=0;i<n1;i++)
    {
        left[i]=array[start+i];
    }
    for(j=0;j<n2;j++)
    {
        right[j]=array[middle+1+j];
    }

    i=0; j=0; k=start;


    while(i<n1 && j<n2)
    {
        if(left[i]<right[j])
        {
            array[k]=left[i];
            i++;
        }
        else
        {
            array[k]=right[j];
            j++;
        }
        k++;
    }

    while(i<n1)
    {
        array[k]=left[i];
        i++; k++;
    }

    while(j<n2)
    {
        array[k]=right[j];
        j++; k++;
    }

}


Output of the C program
                                                                           
                                                                                                     
Enter the item no 1 : 3 Enter the item no 2 : 1 Enter the item no 3 : 4 Enter the item no 4 : 1 Enter the item no 5 : 5 Enter the item no 6 : 9 Enter the item no 7 : 2 Enter the item no 8 : 6 Enter the item no 9 : 5 Enter the item no 10 : 4 The Sorted list is as follows :- The item no 1 of the sorted list is : 1 The item no 2 of the sorted list is : 1 The item no 3 of the sorted list is : 2 The item no 4 of the sorted list is : 3 The item no 5 of the sorted list is : 4 The item no 6 of the sorted list is : 4 The item no 7 of the sorted list is : 5 The item no 8 of the sorted list is : 5 The item no 9 of the sorted list is : 6 The item no 10 of the sorted list is : 9                                                         

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